I have Googled thoroughly and drawn a blank with scheduling when you have less than the required number of workers. Everything is telling me to use the smallest latest start time (apart from the Pearson textbook I'm using which says smallest latest finish time, which I've tried too!). However I just can't get my head around a question from the Pearson textbook (p168 qu. 19 e), also in a past paper (January 2002 qu. 7e). I'm happy with scheduling worker 1 to do A then C and worker 2 to start off on B but could someone please explain to me why I then need to schedule worker 2 to do activity G (instead of activity D as I think it should be)? I've worked it through with activity D there instead and get a solution of 25 hours minimum, so I can see the solution in the book/answer scheme is better by 1 hour. I just can't see how I should know to put G instead of D for worker 2! Any help would be very very much appreciated. It's my first time teaching D1 so I'm struggling to work out how to explain this to pupils. Thanks.