I was doing this question from an MEI past paper with a student. Solve: ln(2+e^x) = 2x I was surprised when he said almost immediately x = ln2, which of course is correct. Since I'm having to do lessons online I couldn't see his working so asked how he got that. His method, ln2 + x = 2x so x = ln2 So a complete misunderstanding of logs but it gives the right answer. If they'd had for example, Solve: ln(6+e^x) = 2x, this couldn't have happened.